Advanced Statistics, If all the 1 pound cans of beans filled by a food processor?
Q. If all the 1 powder cans of beans filled by a food processor have a mean weight of 16.00 ounces with a touchstone deviation of 0.02 ounces, at least what percentage of the cans must hold between 15.80 and 16.20 ounces of beans, assuming the weights
If we arrogate the distribution of the weights of cans of beans is normal with inferior = 16.00 and standard deviation = 0.02
Then z1 = (15.80 - 16.00)/0.02 = -0.20/0.02 = -10
z2 = (16.20 - 16.00)/0.02 = 0.20/0.02 = 10








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